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Derivative of 1/2*sin(2x-1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
sin(2*x - 1)
------------
     2      
$$\frac{\sin{\left(2 x - 1 \right)}}{2}$$
sin(2*x - 1)/2
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    So, the result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
cos(2*x - 1)
$$\cos{\left(2 x - 1 \right)}$$
The second derivative [src]
-2*sin(-1 + 2*x)
$$- 2 \sin{\left(2 x - 1 \right)}$$
The third derivative [src]
-4*cos(-1 + 2*x)
$$- 4 \cos{\left(2 x - 1 \right)}$$