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Derivative of 1/sin(2*x)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   1    
--------
sin(2*x)
$$\frac{1}{\sin{\left(2 x \right)}}$$
1/sin(2*x)
Detail solution
  1. Let .

  2. Apply the power rule: goes to

  3. Then, apply the chain rule. Multiply by :

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    The result of the chain rule is:


The answer is:

The graph
The first derivative [src]
-2*cos(2*x)
-----------
    2      
 sin (2*x) 
$$- \frac{2 \cos{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}$$
The second derivative [src]
  /         2     \
  |    2*cos (2*x)|
4*|1 + -----------|
  |        2      |
  \     sin (2*x) /
-------------------
      sin(2*x)     
$$\frac{4 \left(1 + \frac{2 \cos^{2}{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}\right)}{\sin{\left(2 x \right)}}$$
The third derivative [src]
   /         2     \         
   |    6*cos (2*x)|         
-8*|5 + -----------|*cos(2*x)
   |        2      |         
   \     sin (2*x) /         
-----------------------------
             2               
          sin (2*x)          
$$- \frac{8 \left(5 + \frac{6 \cos^{2}{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}\right) \cos{\left(2 x \right)}}{\sin^{2}{\left(2 x \right)}}$$