Apply the product rule:
dydf(y)g(y)=f(y)dydg(y)+g(y)dydf(y)
f(y)=−y; to find dydf(y):
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The derivative of a constant times a function is the constant times the derivative of the function.
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Apply the power rule: y goes to 1
So, the result is: −1
g(y)=log(y); to find dydg(y):
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The derivative of log(y) is y1.
The result is: −log(y)−1