Mister Exam

Derivative of (-2)sin2x+5ctg6x

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
-2*sin(2*x) + 5*cot(6*x)
$$- 2 \sin{\left(2 x \right)} + 5 \cot{\left(6 x \right)}$$
-2*sin(2*x) + 5*cot(6*x)
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of sine is cosine:

      3. Then, apply the chain rule. Multiply by :

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result of the chain rule is:

      So, the result is:

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. There are multiple ways to do this derivative.

        Method #1

        1. Rewrite the function to be differentiated:

        2. Let .

        3. Apply the power rule: goes to

        4. Then, apply the chain rule. Multiply by :

          1. Rewrite the function to be differentiated:

          2. Apply the quotient rule, which is:

            and .

            To find :

            1. Let .

            2. The derivative of sine is cosine:

            3. Then, apply the chain rule. Multiply by :

              1. The derivative of a constant times a function is the constant times the derivative of the function.

                1. Apply the power rule: goes to

                So, the result is:

              The result of the chain rule is:

            To find :

            1. Let .

            2. The derivative of cosine is negative sine:

            3. Then, apply the chain rule. Multiply by :

              1. The derivative of a constant times a function is the constant times the derivative of the function.

                1. Apply the power rule: goes to

                So, the result is:

              The result of the chain rule is:

            Now plug in to the quotient rule:

          The result of the chain rule is:

        Method #2

        1. Rewrite the function to be differentiated:

        2. Apply the quotient rule, which is:

          and .

          To find :

          1. Let .

          2. The derivative of cosine is negative sine:

          3. Then, apply the chain rule. Multiply by :

            1. The derivative of a constant times a function is the constant times the derivative of the function.

              1. Apply the power rule: goes to

              So, the result is:

            The result of the chain rule is:

          To find :

          1. Let .

          2. The derivative of sine is cosine:

          3. Then, apply the chain rule. Multiply by :

            1. The derivative of a constant times a function is the constant times the derivative of the function.

              1. Apply the power rule: goes to

              So, the result is:

            The result of the chain rule is:

          Now plug in to the quotient rule:

      So, the result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
            2                  
-30 - 30*cot (6*x) - 4*cos(2*x)
$$- 4 \cos{\left(2 x \right)} - 30 \cot^{2}{\left(6 x \right)} - 30$$
The second derivative [src]
  /   /       2     \                    \
8*\45*\1 + cot (6*x)/*cot(6*x) + sin(2*x)/
$$8 \left(45 \left(\cot^{2}{\left(6 x \right)} + 1\right) \cot{\left(6 x \right)} + \sin{\left(2 x \right)}\right)$$
The third derivative [src]
   /                     2                                           \
   |      /       2     \           2      /       2     \           |
16*\- 135*\1 + cot (6*x)/  - 270*cot (6*x)*\1 + cot (6*x)/ + cos(2*x)/
$$16 \left(- 135 \left(\cot^{2}{\left(6 x \right)} + 1\right)^{2} - 270 \left(\cot^{2}{\left(6 x \right)} + 1\right) \cot^{2}{\left(6 x \right)} + \cos{\left(2 x \right)}\right)$$