/ 2\ log\y /
log(y^2)
Let u=y2u = y^{2}u=y2.
The derivative of log(u)\log{\left(u \right)}log(u) is 1u\frac{1}{u}u1.
Then, apply the chain rule. Multiply by ddyy2\frac{d}{d y} y^{2}dydy2:
Apply the power rule: y2y^{2}y2 goes to 2y2 y2y
The result of the chain rule is:
The answer is:
2 - y
-2 --- 2 y
4 -- 3 y