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Identical expressions
log((x- two)/(x+ two))
logarithm of ((x minus 2) divide by (x plus 2))
logarithm of ((x minus two) divide by (x plus two))
logx-2/x+2
log((x-2) divide by (x+2))
Similar expressions
log((x+2)/(x+2))
log((x-2)/(x-2))

The derivative of the function/ log((x-2)/(x+2))

Derivative of log((x-2)/(x+2))

The solution

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   /x - 2\
log|-----|
   \x + 2/

$$\log{\left(\frac{x - 2}{x + 2} \right)}$$

log((x - 2)/(x + 2))

Detail solution

Let $u = \frac{x - 2}{x + 2}$ .
The derivative of $\log{\left(u \right)}$ is $\frac{1}{u}$ .
Then, apply the chain rule. Multiply by $\frac{d}{d x} \frac{x - 2}{x + 2}$ :
1. Apply the quotient rule, which is:
  
  $\frac{d}{d x} \frac{f{\left(x \right)}}{g{\left(x \right)}} = \frac{- f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}}{g^{2}{\left(x \right)}}$
  
  $f{\left(x \right)} = x - 2$ and $g{\left(x \right)} = x + 2$ .
  
  To find $\frac{d}{d x} f{\left(x \right)}$ :
  1. Differentiate $x - 2$ term by term:
    1. The derivative of the constant $-2$ is zero.
    2. Apply the power rule: $x$ goes to $1$
    The result is: $1$
  To find $\frac{d}{d x} g{\left(x \right)}$ :
  1. Differentiate $x + 2$ term by term:
    1. The derivative of the constant $2$ is zero.
    2. Apply the power rule: $x$ goes to $1$
    The result is: $1$
  Now plug in to the quotient rule:
  
  $\frac{4}{\left(x + 2\right)^{2}}$
The result of the chain rule is:

$\frac{4 \left(x + 2\right)}{\left(x - 2\right) \left(x + 2\right)^{2}}$
Now simplify:

$\frac{4}{x^{2} - 4}$

The answer is:

$\frac{4}{x^{2} - 4}$

The graph

Plot the graph f(x)

Plot the graph f'(x)

The first derivative [src]

        /  1      x - 2  \
(x + 2)*|----- - --------|
        |x + 2          2|
        \        (x + 2) /
--------------------------
          x - 2

$$\frac{\left(x + 2\right) \left(- \frac{x - 2}{\left(x + 2\right)^{2}} + \frac{1}{x + 2}\right)}{x - 2}$$

Simplify

The second derivative [src]

/     -2 + x\ /  1        1  \
|-1 + ------|*|------ + -----|
\     2 + x / \-2 + x   2 + x/
------------------------------
            -2 + x

$$\frac{\left(\frac{x - 2}{x + 2} - 1\right) \left(\frac{1}{x + 2} + \frac{1}{x - 2}\right)}{x - 2}$$

Simplify

The third derivative [src]

  /     -2 + x\ /      1          1              1        \
2*|-1 + ------|*|- --------- - -------- - ----------------|
  \     2 + x / |          2          2   (-2 + x)*(2 + x)|
                \  (-2 + x)    (2 + x)                    /
-----------------------------------------------------------
                           -2 + x

$$\frac{2 \left(\frac{x - 2}{x + 2} - 1\right) \left(- \frac{1}{\left(x + 2\right)^{2}} - \frac{1}{\left(x - 2\right) \left(x + 2\right)} - \frac{1}{\left(x - 2\right)^{2}}\right)}{x - 2}$$

Simplify

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Derivative of log((x-2)/(x+2))

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The solution