/x + 1\ log|-----| \x + 2/
log((x + 1)/(x + 2))
Let .
The derivative of is .
Then, apply the chain rule. Multiply by :
Apply the quotient rule, which is:
and .
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
Now plug in to the quotient rule:
The result of the chain rule is:
Now simplify:
The answer is:
/ 1 x + 1 \
(x + 2)*|----- - --------|
|x + 2 2|
\ (x + 2) /
--------------------------
x + 1
/ 1 + x\ / 1 1 \
|-1 + -----|*|----- + -----|
\ 2 + x/ \1 + x 2 + x/
----------------------------
1 + x
/ 1 + x\ / 1 1 1 \
2*|-1 + -----|*|- -------- - -------- - ---------------|
\ 2 + x/ | 2 2 (1 + x)*(2 + x)|
\ (1 + x) (2 + x) /
--------------------------------------------------------
1 + x