/x + 1\ log|-----| \x + 2/
log((x + 1)/(x + 2))
Let .
The derivative of is .
Then, apply the chain rule. Multiply by :
Apply the quotient rule, which is:
and .
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
To find :
Differentiate term by term:
The derivative of the constant is zero.
Apply the power rule: goes to
The result is:
Now plug in to the quotient rule:
The result of the chain rule is:
Now simplify:
The answer is:
/ 1 x + 1 \ (x + 2)*|----- - --------| |x + 2 2| \ (x + 2) / -------------------------- x + 1
/ 1 + x\ / 1 1 \ |-1 + -----|*|----- + -----| \ 2 + x/ \1 + x 2 + x/ ---------------------------- 1 + x
/ 1 + x\ / 1 1 1 \ 2*|-1 + -----|*|- -------- - -------- - ---------------| \ 2 + x/ | 2 2 (1 + x)*(2 + x)| \ (1 + x) (2 + x) / -------------------------------------------------------- 1 + x