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Derivative of ln((2*x)/(x+1))

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   / 2*x \
log|-----|
   \x + 1/
$$\log{\left(\frac{2 x}{x + 1} \right)}$$
log((2*x)/(x + 1))
Detail solution
  1. Let .

  2. The derivative of is .

  3. Then, apply the chain rule. Multiply by :

    1. Apply the quotient rule, which is:

      and .

      To find :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      To find :

      1. Differentiate term by term:

        1. The derivative of the constant is zero.

        2. Apply the power rule: goes to

        The result is:

      Now plug in to the quotient rule:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
        /  2       2*x   \
(x + 1)*|----- - --------|
        |x + 1          2|
        \        (x + 1) /
--------------------------
           2*x            
$$\frac{\left(x + 1\right) \left(- \frac{2 x}{\left(x + 1\right)^{2}} + \frac{2}{x + 1}\right)}{2 x}$$
The second derivative [src]
/       x  \ /1     1  \
|-1 + -----|*|- + -----|
\     1 + x/ \x   1 + x/
------------------------
           x            
$$\frac{\left(\frac{x}{x + 1} - 1\right) \left(\frac{1}{x + 1} + \frac{1}{x}\right)}{x}$$
The third derivative [src]
  /       x  \ /  1       1           1    \
2*|-1 + -----|*|- -- - -------- - ---------|
  \     1 + x/ |   2          2   x*(1 + x)|
               \  x    (1 + x)             /
--------------------------------------------
                     x                      
$$\frac{2 \left(\frac{x}{x + 1} - 1\right) \left(- \frac{1}{\left(x + 1\right)^{2}} - \frac{1}{x \left(x + 1\right)} - \frac{1}{x^{2}}\right)}{x}$$