Derivative of 4*x(1-x)^2

1. Apply the product rule:

   $$\frac{d}{d x} f{\left(x \right)} g{\left(x \right)} = f{\left(x \right)} \frac{d}{d x} g{\left(x \right)} + g{\left(x \right)} \frac{d}{d x} f{\left(x \right)}$$

   $f{\left(x \right)} = 4 x$; to find $\frac{d}{d x} f{\left(x \right)}$:

   1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: $x$ goes to $1$

      So, the result is: $4$

   $g{\left(x \right)} = \left(1 - x\right)^{2}$; to find $\frac{d}{d x} g{\left(x \right)}$:

   1. Let $u = 1 - x$.

   2. Apply the power rule: $u^{2}$ goes to $2 u$

   3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(1 - x\right)$:

      1. Differentiate $1 - x$ term by term:

         1. The derivative of the constant $1$ is zero.

         2. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $-1$

         The result is: $-1$

      The result of the chain rule is:

      $$2 x - 2$$

   The result is: $4 x \left(2 x - 2\right) + 4 \left(1 - x\right)^{2}$

2. Now simplify:

   $$4 \left(x - 1\right) \left(3 x - 1\right)$$

The answer is:

$$4 \left(x - 1\right) \left(3 x - 1\right)$$