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Derivative of 5*cos(4*x)-2+5x

Function f() - derivative -N order at the point
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The solution

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5*cos(4*x) - 2 + 5*x
5x+(5cos(4x)2)5 x + \left(5 \cos{\left(4 x \right)} - 2\right)
5*cos(4*x) - 2 + 5*x
Detail solution
  1. Differentiate 5x+(5cos(4x)2)5 x + \left(5 \cos{\left(4 x \right)} - 2\right) term by term:

    1. Differentiate 5cos(4x)25 \cos{\left(4 x \right)} - 2 term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Let u=4xu = 4 x.

        2. The derivative of cosine is negative sine:

          dducos(u)=sin(u)\frac{d}{d u} \cos{\left(u \right)} = - \sin{\left(u \right)}

        3. Then, apply the chain rule. Multiply by ddx4x\frac{d}{d x} 4 x:

          1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: xx goes to 11

            So, the result is: 44

          The result of the chain rule is:

          4sin(4x)- 4 \sin{\left(4 x \right)}

        So, the result is: 20sin(4x)- 20 \sin{\left(4 x \right)}

      2. The derivative of the constant 2-2 is zero.

      The result is: 20sin(4x)- 20 \sin{\left(4 x \right)}

    2. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Apply the power rule: xx goes to 11

      So, the result is: 55

    The result is: 520sin(4x)5 - 20 \sin{\left(4 x \right)}


The answer is:

520sin(4x)5 - 20 \sin{\left(4 x \right)}

The graph
02468-8-6-4-2-1010-100100
The first derivative [src]
5 - 20*sin(4*x)
520sin(4x)5 - 20 \sin{\left(4 x \right)}
The second derivative [src]
-80*cos(4*x)
80cos(4x)- 80 \cos{\left(4 x \right)}
The third derivative [src]
320*sin(4*x)
320sin(4x)320 \sin{\left(4 x \right)}