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Derivative of 5*cos(4x+2)+9

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The solution

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5*cos(4*x + 2) + 9
$$5 \cos{\left(4 x + 2 \right)} + 9$$
5*cos(4*x + 2) + 9
Detail solution
  1. Differentiate term by term:

    1. The derivative of a constant times a function is the constant times the derivative of the function.

      1. Let .

      2. The derivative of cosine is negative sine:

      3. Then, apply the chain rule. Multiply by :

        1. Differentiate term by term:

          1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: goes to

            So, the result is:

          2. The derivative of the constant is zero.

          The result is:

        The result of the chain rule is:

      So, the result is:

    2. The derivative of the constant is zero.

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
-20*sin(4*x + 2)
$$- 20 \sin{\left(4 x + 2 \right)}$$
The second derivative [src]
-80*cos(2*(1 + 2*x))
$$- 80 \cos{\left(2 \left(2 x + 1\right) \right)}$$
The third derivative [src]
320*sin(2*(1 + 2*x))
$$320 \sin{\left(2 \left(2 x + 1\right) \right)}$$