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Derivative of f(x)=(3y^2+1)(2^y+1)

Function f() - derivative -N order at the point
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The graph:

from to

Piecewise:

The solution

You have entered [src]
/   2    \ / y    \
\3*y  + 1/*\2  + 1/
$$\left(2^{y} + 1\right) \left(3 y^{2} + 1\right)$$
(3*y^2 + 1)*(2^y + 1)
Detail solution
  1. Apply the product rule:

    ; to find :

    1. Differentiate term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      2. The derivative of the constant is zero.

      The result is:

    ; to find :

    1. Differentiate term by term:

      1. The derivative of the constant is zero.

      The result is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
    / y    \    y /   2    \       
6*y*\2  + 1/ + 2 *\3*y  + 1/*log(2)
$$2^{y} \left(3 y^{2} + 1\right) \log{\left(2 \right)} + 6 y \left(2^{y} + 1\right)$$
The second derivative [src]
       y    y    2    /       2\         y       
6 + 6*2  + 2 *log (2)*\1 + 3*y / + 12*y*2 *log(2)
$$12 \cdot 2^{y} y \log{\left(2 \right)} + 2^{y} \left(3 y^{2} + 1\right) \log{\left(2 \right)}^{2} + 6 \cdot 2^{y} + 6$$
The third derivative [src]
 y /        2    /       2\              \       
2 *\18 + log (2)*\1 + 3*y / + 18*y*log(2)/*log(2)
$$2^{y} \left(18 y \log{\left(2 \right)} + \left(3 y^{2} + 1\right) \log{\left(2 \right)}^{2} + 18\right) \log{\left(2 \right)}$$