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Derivative of exp^(x^2+2x-1)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
  2          
 x  + 2*x - 1
E            
$$e^{\left(x^{2} + 2 x\right) - 1}$$
E^(x^2 + 2*x - 1)
Detail solution
  1. Let .

  2. The derivative of is itself.

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. Differentiate term by term:

        1. Apply the power rule: goes to

        2. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result is:

      2. The derivative of the constant is zero.

      The result is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
            2          
           x  + 2*x - 1
(2 + 2*x)*e            
$$\left(2 x + 2\right) e^{\left(x^{2} + 2 x\right) - 1}$$
The second derivative [src]
                          2      
  /             2\  -1 + x  + 2*x
2*\1 + 2*(1 + x) /*e             
$$2 \left(2 \left(x + 1\right)^{2} + 1\right) e^{x^{2} + 2 x - 1}$$
5-я производная [src]
                                                 2      
          /              4             2\  -1 + x  + 2*x
8*(1 + x)*\15 + 4*(1 + x)  + 20*(1 + x) /*e             
$$8 \left(x + 1\right) \left(4 \left(x + 1\right)^{4} + 20 \left(x + 1\right)^{2} + 15\right) e^{x^{2} + 2 x - 1}$$
The third derivative [src]
                                  2      
          /             2\  -1 + x  + 2*x
4*(1 + x)*\3 + 2*(1 + x) /*e             
$$4 \left(x + 1\right) \left(2 \left(x + 1\right)^{2} + 3\right) e^{x^{2} + 2 x - 1}$$