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Derivative of (e^(2x)^2)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
 /     2\
 \(2*x) /
E        
$$e^{\left(2 x\right)^{2}}$$
E^((2*x)^2)
Detail solution
  1. Let .

  2. The derivative of is itself.

  3. Then, apply the chain rule. Multiply by :

    1. Let .

    2. Apply the power rule: goes to

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      The result of the chain rule is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The graph
The first derivative [src]
     /     2\
     \(2*x) /
8*x*e        
$$8 x e^{\left(2 x\right)^{2}}$$
The second derivative [src]
              /     2\
  /       2\  \(2*x) /
8*\1 + 8*x /*e        
$$8 \left(8 x^{2} + 1\right) e^{\left(2 x\right)^{2}}$$
The third derivative [src]
                 /     2\
     /       2\  \(2*x) /
64*x*\3 + 8*x /*e        
$$64 x \left(8 x^{2} + 3\right) e^{\left(2 x\right)^{2}}$$