Detail solution
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Let .
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Apply the power rule: goes to
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Then, apply the chain rule. Multiply by :
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Differentiate term by term:
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Let .
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The derivative of is itself.
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Then, apply the chain rule. Multiply by :
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The derivative of sine is cosine:
The result of the chain rule is:
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The derivative of a constant times a function is the constant times the derivative of the function.
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Apply the power rule: goes to
So, the result is:
The result is:
The result of the chain rule is:
Now simplify:
The answer is:
The first derivative
[src]
2
/ sin(x) \ / sin(x)\
\E + 3*x/ *\9 + 3*cos(x)*e /
$$\left(e^{\sin{\left(x \right)}} + 3 x\right)^{2} \left(3 e^{\sin{\left(x \right)}} \cos{\left(x \right)} + 9\right)$$
The second derivative
[src]
/ 2 \
| / sin(x)\ / 2 \ / sin(x)\ sin(x)| / sin(x)\
3*\2*\3 + cos(x)*e / - \- cos (x) + sin(x)/*\3*x + e /*e /*\3*x + e /
$$3 \left(3 x + e^{\sin{\left(x \right)}}\right) \left(- \left(3 x + e^{\sin{\left(x \right)}}\right) \left(\sin{\left(x \right)} - \cos^{2}{\left(x \right)}\right) e^{\sin{\left(x \right)}} + 2 \left(e^{\sin{\left(x \right)}} \cos{\left(x \right)} + 3\right)^{2}\right)$$
The third derivative
[src]
/ 3 2 \
| / sin(x)\ / sin(x)\ / 2 \ sin(x) / sin(x)\ / 2 \ / sin(x)\ sin(x)|
3*\2*\3 + cos(x)*e / - \3*x + e / *\1 - cos (x) + 3*sin(x)/*cos(x)*e - 6*\3 + cos(x)*e /*\- cos (x) + sin(x)/*\3*x + e /*e /
$$3 \left(- \left(3 x + e^{\sin{\left(x \right)}}\right)^{2} \left(3 \sin{\left(x \right)} - \cos^{2}{\left(x \right)} + 1\right) e^{\sin{\left(x \right)}} \cos{\left(x \right)} - 6 \left(3 x + e^{\sin{\left(x \right)}}\right) \left(e^{\sin{\left(x \right)}} \cos{\left(x \right)} + 3\right) \left(\sin{\left(x \right)} - \cos^{2}{\left(x \right)}\right) e^{\sin{\left(x \right)}} + 2 \left(e^{\sin{\left(x \right)}} \cos{\left(x \right)} + 3\right)^{3}\right)$$