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cos(x-pi/3)

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cos(x-pi/3)

What you mean?

Derivative of cos(x-pi/3)

Function f() - derivative -N order at the point
v

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The solution

You have entered [src]
   /    pi\
cos|x - --|
   \    3 /
cos(xπ3)\cos{\left(x - \frac{\pi}{3} \right)}
d /   /    pi\\
--|cos|x - --||
dx\   \    3 //
ddxcos(xπ3)\frac{d}{d x} \cos{\left(x - \frac{\pi}{3} \right)}
Detail solution
  1. Let u=xπ3u = x - \frac{\pi}{3}.

  2. The derivative of cosine is negative sine:

    dducos(u)=sin(u)\frac{d}{d u} \cos{\left(u \right)} = - \sin{\left(u \right)}

  3. Then, apply the chain rule. Multiply by ddx(xπ3)\frac{d}{d x} \left(x - \frac{\pi}{3}\right):

    1. Differentiate xπ3x - \frac{\pi}{3} term by term:

      1. Apply the power rule: xx goes to 11

      2. The derivative of the constant π3- \frac{\pi}{3} is zero.

      The result is: 11

    The result of the chain rule is:

    sin(xπ3)- \sin{\left(x - \frac{\pi}{3} \right)}

  4. Now simplify:

    cos(x+π6)\cos{\left(x + \frac{\pi}{6} \right)}


The answer is:

cos(x+π6)\cos{\left(x + \frac{\pi}{6} \right)}

The graph
02468-8-6-4-2-10102-2
The first derivative [src]
    /    pi\
-sin|x - --|
    \    3 /
sin(xπ3)- \sin{\left(x - \frac{\pi}{3} \right)}
The second derivative [src]
    /    pi\
-sin|x + --|
    \    6 /
sin(x+π6)- \sin{\left(x + \frac{\pi}{6} \right)}
The third derivative [src]
    /    pi\
-cos|x + --|
    \    6 /
cos(x+π6)- \cos{\left(x + \frac{\pi}{6} \right)}
The graph
Derivative of cos(x-pi/3)