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Derivative of cos(3/x+p/4)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
   /3   p\
cos|- + -|
   \x   4/
$$\cos{\left(\frac{p}{4} + \frac{3}{x} \right)}$$
cos(3/x + p/4)
Detail solution
  1. Let .

  2. The derivative of cosine is negative sine:

  3. Then, apply the chain rule. Multiply by :

    1. Differentiate term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      2. The derivative of the constant is zero.

      The result is:

    The result of the chain rule is:

  4. Now simplify:


The answer is:

The first derivative [src]
     /3   p\
3*sin|- + -|
     \x   4/
------------
      2     
     x      
$$\frac{3 \sin{\left(\frac{p}{4} + \frac{3}{x} \right)}}{x^{2}}$$
The second derivative [src]
   /                    /3   p\\
   |               3*cos|- + -||
   |     /3   p\        \x   4/|
-3*|2*sin|- + -| + ------------|
   \     \x   4/        x      /
--------------------------------
                3               
               x                
$$- \frac{3 \left(2 \sin{\left(\frac{p}{4} + \frac{3}{x} \right)} + \frac{3 \cos{\left(\frac{p}{4} + \frac{3}{x} \right)}}{x}\right)}{x^{3}}$$
The third derivative [src]
  /                    /3   p\        /3   p\\
  |               3*sin|- + -|   6*cos|- + -||
  |     /3   p\        \x   4/        \x   4/|
9*|2*sin|- + -| - ------------ + ------------|
  |     \x   4/         2             x      |
  \                    x                     /
----------------------------------------------
                       4                      
                      x                       
$$\frac{9 \left(2 \sin{\left(\frac{p}{4} + \frac{3}{x} \right)} + \frac{6 \cos{\left(\frac{p}{4} + \frac{3}{x} \right)}}{x} - \frac{3 \sin{\left(\frac{p}{4} + \frac{3}{x} \right)}}{x^{2}}\right)}{x^{4}}$$