Detail solution
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Let .
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Apply the power rule: goes to
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Then, apply the chain rule. Multiply by :
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Let .
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The derivative of cosine is negative sine:
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Then, apply the chain rule. Multiply by :
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The derivative of cosine is negative sine:
The result of the chain rule is:
The result of the chain rule is:
Now simplify:
The answer is:
The first derivative
[src]
2*cos(cos(x))*sin(x)*sin(cos(x))
$$2 \sin{\left(x \right)} \sin{\left(\cos{\left(x \right)} \right)} \cos{\left(\cos{\left(x \right)} \right)}$$
The second derivative
[src]
/ 2 2 2 2 \
2*\sin (x)*sin (cos(x)) - cos (cos(x))*sin (x) + cos(x)*cos(cos(x))*sin(cos(x))/
$$2 \left(\sin^{2}{\left(x \right)} \sin^{2}{\left(\cos{\left(x \right)} \right)} - \sin^{2}{\left(x \right)} \cos^{2}{\left(\cos{\left(x \right)} \right)} + \sin{\left(\cos{\left(x \right)} \right)} \cos{\left(x \right)} \cos{\left(\cos{\left(x \right)} \right)}\right)$$
The third derivative
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/ 2 2 2 \
2*\-cos(cos(x))*sin(cos(x)) - 3*cos (cos(x))*cos(x) + 3*sin (cos(x))*cos(x) - 4*sin (x)*cos(cos(x))*sin(cos(x))/*sin(x)
$$2 \left(- 4 \sin^{2}{\left(x \right)} \sin{\left(\cos{\left(x \right)} \right)} \cos{\left(\cos{\left(x \right)} \right)} + 3 \sin^{2}{\left(\cos{\left(x \right)} \right)} \cos{\left(x \right)} - \sin{\left(\cos{\left(x \right)} \right)} \cos{\left(\cos{\left(x \right)} \right)} - 3 \cos{\left(x \right)} \cos^{2}{\left(\cos{\left(x \right)} \right)}\right) \sin{\left(x \right)}$$