The first derivative
[src]
$$- \frac{4 x}{4 x^{4} + 1}$$
The second derivative
[src]
/ 4 \
| 16*x |
4*|-1 + --------|
| 4|
\ 1 + 4*x /
-----------------
4
1 + 4*x
$$\frac{4 \left(\frac{16 x^{4}}{4 x^{4} + 1} - 1\right)}{4 x^{4} + 1}$$
The third derivative
[src]
/ 4 \
3 | 32*x |
64*x *|5 - --------|
| 4|
\ 1 + 4*x /
--------------------
2
/ 4\
\1 + 4*x /
$$\frac{64 x^{3} \left(- \frac{32 x^{4}}{4 x^{4} + 1} + 5\right)}{\left(4 x^{4} + 1\right)^{2}}$$