Find the derivative of f(x) = 9x + 5 at x = 7.
Can someone please show me a simple way to do this o_O
The derivative of a variable raised to exponent of n, x^n is equal to the product of n and x raised to exponent of n-1.
d(x^n) = (n)(x^n-1)
So, from the given
d(9x + 5) = (1)(9x^1-0) + 5(0)
Differentiate term by term:
The derivative of a constant times a function is the constant times the derivative of the function.
Apply the power rule: goes to
So, the result is:
The derivative of the constant is zero.
The result is:
The answer is: