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Derivative of (7x+6)*sin(5x+4)

Function f() - derivative -N order at the point
v

The graph:

from to

Piecewise:

The solution

You have entered [src]
(7*x + 6)*sin(5*x + 4)
$$\left(7 x + 6\right) \sin{\left(5 x + 4 \right)}$$
(7*x + 6)*sin(5*x + 4)
Detail solution
  1. Apply the product rule:

    ; to find :

    1. Differentiate term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. Apply the power rule: goes to

        So, the result is:

      2. The derivative of the constant is zero.

      The result is:

    ; to find :

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        2. The derivative of the constant is zero.

        The result is:

      The result of the chain rule is:

    The result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
7*sin(5*x + 4) + 5*(7*x + 6)*cos(5*x + 4)
$$5 \left(7 x + 6\right) \cos{\left(5 x + 4 \right)} + 7 \sin{\left(5 x + 4 \right)}$$
The second derivative [src]
5*(14*cos(4 + 5*x) - 5*(6 + 7*x)*sin(4 + 5*x))
$$5 \left(- 5 \left(7 x + 6\right) \sin{\left(5 x + 4 \right)} + 14 \cos{\left(5 x + 4 \right)}\right)$$
The third derivative [src]
-25*(21*sin(4 + 5*x) + 5*(6 + 7*x)*cos(4 + 5*x))
$$- 25 \left(5 \left(7 x + 6\right) \cos{\left(5 x + 4 \right)} + 21 \sin{\left(5 x + 4 \right)}\right)$$