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Derivative of 40pi*cos((pit)/6)

Function f() - derivative -N order at the point
v

The graph:

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Piecewise:

The solution

You have entered [src]
         /pi*t\
40*pi*cos|----|
         \ 6  /
$$40 \pi \cos{\left(\frac{\pi t}{6} \right)}$$
(40*pi)*cos((pi*t)/6)
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let .

    2. The derivative of cosine is negative sine:

    3. Then, apply the chain rule. Multiply by :

      1. The derivative of a constant times a function is the constant times the derivative of the function.

        1. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        So, the result is:

      The result of the chain rule is:

    So, the result is:

  2. Now simplify:


The answer is:

The graph
The first derivative [src]
      2    /pi*t\
-20*pi *sin|----|
           \ 6  /
-----------------
        3        
$$- \frac{20 \pi^{2} \sin{\left(\frac{\pi t}{6} \right)}}{3}$$
The second derivative [src]
      3    /pi*t\
-10*pi *cos|----|
           \ 6  /
-----------------
        9        
$$- \frac{10 \pi^{3} \cos{\left(\frac{\pi t}{6} \right)}}{9}$$
The third derivative [src]
    4    /pi*t\
5*pi *sin|----|
         \ 6  /
---------------
       27      
$$\frac{5 \pi^{4} \sin{\left(\frac{\pi t}{6} \right)}}{27}$$