Derivative of √(2x²-4x+1)

1. Let $u = 2 x^{2} - 4 x + 1$.

2. Apply the power rule: $\sqrt{u}$ goes to $\frac{1}{2 \sqrt{u}}$

3. Then, apply the chain rule. Multiply by $\frac{d}{d x} \left(2 x^{2} - 4 x + 1\right)$:

   1. Differentiate $2 x^{2} - 4 x + 1$ term by term:

      1. The derivative of a constant times a function is the constant times the derivative of the function.

         1. Apply the power rule: $x^{2}$ goes to $2 x$

         So, the result is: $4 x$

      2. The derivative of a constant times a function is the constant times the derivative of the function.

         1. The derivative of a constant times a function is the constant times the derivative of the function.

            1. Apply the power rule: $x$ goes to $1$

            So, the result is: $4$

         So, the result is: $-4$

      3. The derivative of the constant $1$ is zero.

      The result is: $4 x - 4$

   The result of the chain rule is:

   $$\frac{4 x - 4}{2 \sqrt{2 x^{2} - 4 x + 1}}$$

4. Now simplify:

   $$\frac{2 \left(x - 1\right)}{\sqrt{2 x^{2} - 4 x + 1}}$$

The answer is: