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Derivative of 2sin(3-4*x)

Function f() - derivative -N order at the point
v

The graph:

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The solution

You have entered [src]
2*sin(3 - 4*x)
$$2 \sin{\left(3 - 4 x \right)}$$
2*sin(3 - 4*x)
Detail solution
  1. The derivative of a constant times a function is the constant times the derivative of the function.

    1. Let .

    2. The derivative of sine is cosine:

    3. Then, apply the chain rule. Multiply by :

      1. Differentiate term by term:

        1. The derivative of the constant is zero.

        2. The derivative of a constant times a function is the constant times the derivative of the function.

          1. Apply the power rule: goes to

          So, the result is:

        The result is:

      The result of the chain rule is:

    So, the result is:


The answer is:

The graph
The first derivative [src]
-8*cos(-3 + 4*x)
$$- 8 \cos{\left(4 x - 3 \right)}$$
The second derivative [src]
32*sin(-3 + 4*x)
$$32 \sin{\left(4 x - 3 \right)}$$
The third derivative [src]
128*cos(-3 + 4*x)
$$128 \cos{\left(4 x - 3 \right)}$$