Mister Exam

z=ln(x+y) canonical form

The teacher will be very surprised to see your correct solution 😉

v

The graph:

x: [, ]
y: [, ]
z: [, ]

Quality:

 (Number of points on the axis)

Plot type:

The solution

You have entered [src]
z - log(x + y) = 0
$$z - \log{\left(x + y \right)} = 0$$
z - log(x + y) = 0