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Canonical form:
(2^x+1)/ln(2)
2y^2-x=0
6x^2+6y^2-22x+y=7
3x^2+8xy-3y^2
Plot:
z=4*(x-y)-x^2-y^2
(x^2+y^2-1)^3=x^2*y^3
z=/sqrt(3*x+2*y+2)
y=y^x/x
Identical expressions
(two ^x+ one)/ln(two)
(2 to the power of x plus 1) divide by ln(2)
(two to the power of x plus one) divide by ln(two)
(2x+1)/ln(2)
2x+1/ln2
2^x+1/ln2
(2^x+1) divide by ln(2)
Similar expressions
(2^x-1)/ln(2)

Canonical form/ (2^x+1)/ln(2)

(2^x+1)/ln(2) canonical form

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The solution

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     x    
1 + 2     
------ = 0
log(2)

$$\frac{2^{x} + 1}{\log{\left(2 \right)}} = 0$$

(2^x + 1)/log(2) = 0