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5xy-5x-2y+2/(10x^2-9x+2) canonical form

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                    2                   
-5*x - 2*y + --------------- + 5*x*y = 0
                           2            
             2 - 9*x + 10*x             
$$5 x y - 5 x - 2 y + \frac{2}{10 x^{2} - 9 x + 2} = 0$$
5*x*y - 5*x - 2*y + 2/(10*x^2 - 9*x + 2) = 0