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x^2+y^2=42; x+y=6

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The solution

You have entered [src]
 2    2     
x  + y  = 42
$$x^{2} + y^{2} = 42$$
x + y = 6
$$x + y = 6$$
x + y = 6
Rapid solution
$$x_{1} = 3 - 2 \sqrt{3}$$
=
$$3 - 2 \sqrt{3}$$
=
-0.464101615137755

$$y_{1} = 3 + 2 \sqrt{3}$$
=
$$3 + 2 \sqrt{3}$$
=
6.46410161513775
$$x_{2} = 3 + 2 \sqrt{3}$$
=
$$3 + 2 \sqrt{3}$$
=
6.46410161513775

$$y_{2} = 3 - 2 \sqrt{3}$$
=
$$3 - 2 \sqrt{3}$$
=
-0.464101615137755
Numerical answer [src]
x1 = -0.4641016151377546
y1 = 6.464101615137755
x1 = -0.4641016151377546
y1 = 6.464101615137755