Given the system of equations $$9 x - 14 y = - 39 x - 14 y$$ $$- a y + 2 x = - a y - 62 x$$
We give the system of equations to the canonical form $$48 x = 0$$ $$64 x = 0$$ Rewrite the system of linear equations as the matrix form $$\left[\begin{matrix}48 & 0\\64 & 0\end{matrix}\right]$$
It is almost ready, all we have to do is to find variables, solving the elementary equations: $$48 x_{1} = 0$$ $$64 x_{1} = 0$$ We get the answer: $$x_{1} = 0$$ $$x_{1} = 0$$
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