Integral of √x dx

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$$\int\limits_{0}^{1} \sqrt{x}\, dx$$

Integral(sqrt(x), (x, 0, 1))

Detail solution

The integral of $x^{n}$ is $\frac{x^{n + 1}}{n + 1}$ when $n \neq -1$ :

$\int \sqrt{x}\, dx = \frac{2 x^{\frac{3}{2}}}{3}$
Add the constant of integration:

$\frac{2 x^{\frac{3}{2}}}{3}+ \mathrm{constant}$

The answer is:

$\frac{2 x^{\frac{3}{2}}}{3}+ \mathrm{constant}$

The answer (Indefinite) [src]

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$${{2\,x^{{{3}\over{2}}}}\over{3}}$$

Simplify

The graph

Plot the graph f(x)

The answer [src]

2/3

$${{2}\over{3}}$$

2/3

$$\frac{2}{3}$$

Simplify

Numerical answer [src]

0.666666666666667

0.666666666666667

The graph

Use the examples entering the upper and lower limits of integration.