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- Improper integral
- Double Integral
- Triple Integral
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How to use it?
- Integral of d{x}:
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Integral of x^3*e^(x^4)
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Integral of (-1+u)/(1+u^2)
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Integral of x*e^(4*x)
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Integral of e^(-x/2)
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Identical expressions
- -x^3dx/sin^ two (2x^ four + one)
- minus x cubed dx divide by sinus of squared (2x to the power of 4 plus 1)
- minus x cubed dx divide by sinus of to the power of two (2x to the power of four plus one)
- -x3dx/sin2(2x4+1)
- -x3dx/sin22x4+1
- -x³dx/sin²(2x⁴+1)
- -x to the power of 3dx/sin to the power of 2(2x to the power of 4+1)
- -x^3dx/sin^22x^4+1
- -x^3dx divide by sin^2(2x^4+1)
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Similar expressions
- -x^3dx/sin^2(2x^4-1)
- x^3dx/sin^2(2x^4+1)
Integral of -x^3dx/sin^2(2x^4+1) dx
The solution
You have entered
[src]
0 / | | 3 1 | -x *1*-------------- dx | 2/ 4 \ | sin \2*x + 1/ | / 0
$$\int\limits_{0}^{0} - x^{3} \cdot 1 \cdot \frac{1}{\sin^{2}{\left(2 x^{4} + 1 \right)}}\, dx$$
Integral(-x^3*1/sin(2*x^4 + 1)^2, (x, 0, 0))
The answer (Indefinite)
[src]
/ /1 4\ | tan|- + x | | 3 1 \2 / 1 | -x *1*-------------- dx = C - ----------- + -------------- | 2/ 4 \ 16 /1 4\ | sin \2*x + 1/ 16*tan|- + x | | \2 / /
$${{\sin \left(4\,x^4+2\right)}\over{4\,\sin ^2\left(4\,x^4+2\right)+
4\,\cos ^2\left(4\,x^4+2\right)-8\,\cos \left(4\,x^4+2\right)+4}}$$
The graph
The graph
Use the examples entering the upper and lower limits of integration.