Mister Exam
log5(3x+1)+log5(1/(72x^2)+1)≥log5(1/(24x)+1) inequation
The solution
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[src]
/ 1 \
log|----- + 1| / 1 \
| 2 | log|---- + 1|
log(3*x + 1) \72*x / \24*x /
------------ + -------------- >= -------------
log(5) log(5) log(5)
$$\frac{\log{\left(1 + \frac{1}{72 x^{2}} \right)}}{\log{\left(5 \right)}} + \frac{\log{\left(3 x + 1 \right)}}{\log{\left(5 \right)}} \geq \frac{\log{\left(1 + \frac{1}{24 x} \right)}}{\log{\left(5 \right)}}$$
log(1 + 1/(72*x^2))/log(5) + log(3*x + 1)/log(5) >= log(1 + 1/(24*x))/log(5)
Solving inequality on a graph