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Inequation
:
log0.3(x+6)>=log0.3(4-x)
2*20^x-17*10^x-2*8^x+8*5^x+17*4^x-8*2^x<=0
((log0.5)(x)^2)+log0.5(x-2)<=0
log0.5^2(x)+log0.5(x-2)<=0
Identical expressions
log0. three (x+ six)>=log0. three (four -x)
logarithm of 0.3(x plus 6) greater than or equal to logarithm of 0.3(4 minus x)
logarithm of 0. three (x plus six) greater than or equal to logarithm of 0. three (four minus x)
log0.3x+6>=log0.34-x
Similar expressions
log0.3(x+6)>=log0.3(4+x)
log0.3(x-6)>=log0.3(4-x)
Solving inequalities
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log0.3(x+6)>=log0.3(4-x)
log0.3(x+6)>=log0.3(4-x) inequation
+ inequation
Solve the inequality!
A inequation with variable
The solution
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[src]
log(0.0)*3*(x + 6) >= log(0.0)*3*(4 - x)
$$3 \log{\left(0.0 \right)} \left(x + 6\right) \geq 3 \log{\left(0.0 \right)} \left(4 - x\right)$$
(3*log(0.0))*(x + 6) >= (3*log(0.0))*(4 - x)