Mister Exam

Graphing y = tg(x/4)

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The graph:

from to

Intersection points:

does show?

Piecewise:

The solution

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$$f{\left(x \right)} = \tan{\left(\frac{x}{4} \right)}$$
f = tan(x/4)
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis X at f = 0
so we need to solve the equation:
$$\tan{\left(\frac{x}{4} \right)} = 0$$
Solve this equation
The points of intersection with the axis X:

Analytical solution
$$x_{1} = 0$$
Numerical solution
$$x_{1} = -25.1327412287183$$
$$x_{2} = -50.2654824574367$$
$$x_{3} = -62.8318530717959$$
$$x_{4} = 25.1327412287183$$
$$x_{5} = 87.9645943005142$$
$$x_{6} = -37.6991118430775$$
$$x_{7} = -87.9645943005142$$
$$x_{8} = -100.530964914873$$
$$x_{9} = -75.398223686155$$
$$x_{10} = 50.2654824574367$$
$$x_{11} = 62.8318530717959$$
$$x_{12} = 0$$
$$x_{13} = 75.398223686155$$
$$x_{14} = 12.5663706143592$$
$$x_{15} = -12.5663706143592$$
$$x_{16} = 100.530964914873$$
$$x_{17} = 37.6991118430775$$
The points of intersection with the Y axis coordinate
The graph crosses Y axis when x equals 0:
substitute x = 0 to tan(x/4).
$$\tan{\left(\frac{0}{4} \right)}$$
The result:
$$f{\left(0 \right)} = 0$$
The point:
(0, 0)
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d x} f{\left(x \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d x} f{\left(x \right)} = $$
the first derivative
$$\frac{\tan^{2}{\left(\frac{x}{4} \right)}}{4} + \frac{1}{4} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d x^{2}} f{\left(x \right)} = $$
the second derivative
$$\frac{\left(\tan^{2}{\left(\frac{x}{4} \right)} + 1\right) \tan{\left(\frac{x}{4} \right)}}{8} = 0$$
Solve this equation
The roots of this equation
$$x_{1} = 0$$

Сonvexity and concavity intervals:
Let’s find the intervals where the function is convex or concave, for this look at the behaviour of the function at the inflection points:
Concave at the intervals
$$\left[0, \infty\right)$$
Convex at the intervals
$$\left(-\infty, 0\right]$$
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at x->+oo and x->-oo
$$\lim_{x \to -\infty} \tan{\left(\frac{x}{4} \right)} = \left\langle -\infty, \infty\right\rangle$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = \left\langle -\infty, \infty\right\rangle$$
$$\lim_{x \to \infty} \tan{\left(\frac{x}{4} \right)} = \left\langle -\infty, \infty\right\rangle$$
Let's take the limit
so,
equation of the horizontal asymptote on the right:
$$y = \left\langle -\infty, \infty\right\rangle$$
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of tan(x/4), divided by x at x->+oo and x ->-oo
$$\lim_{x \to -\infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right) = \lim_{x \to -\infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right)$$
Let's take the limit
so,
inclined asymptote equation on the left:
$$y = x \lim_{x \to -\infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right)$$
$$\lim_{x \to \infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right) = \lim_{x \to \infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right)$$
Let's take the limit
so,
inclined asymptote equation on the right:
$$y = x \lim_{x \to \infty}\left(\frac{\tan{\left(\frac{x}{4} \right)}}{x}\right)$$
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-x) и f = -f(-x).
So, check:
$$\tan{\left(\frac{x}{4} \right)} = - \tan{\left(\frac{x}{4} \right)}$$
- No
$$\tan{\left(\frac{x}{4} \right)} = \tan{\left(\frac{x}{4} \right)}$$
- No
so, the function
not is
neither even, nor odd
The graph
Graphing y = tg(x/4)