Mister Exam
Graphing y = (e^y)^0,5
The solution
The graph of the function
The points of intersection with the X-axis coordinate
Graph of the function intersects the axis Y at f = 0
so we need to solve the equation:
$$\sqrt{e^{y}} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis Y
so we need to solve the equation:
$$\sqrt{e^{y}} = 0$$
Solve this equation
Solution is not found,
it's possible that the graph doesn't intersect the axis Y
Extrema of the function
In order to find the extrema, we need to solve the equation
$$\frac{d}{d y} f{\left(y \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d y} f{\left(y \right)} = $$
the first derivative
$$\frac{e^{\frac{y}{2}}}{2} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
$$\frac{d}{d y} f{\left(y \right)} = 0$$
(the derivative equals zero),
and the roots of this equation are the extrema of this function:
$$\frac{d}{d y} f{\left(y \right)} = $$
the first derivative
$$\frac{e^{\frac{y}{2}}}{2} = 0$$
Solve this equation
Solutions are not found,
function may have no extrema
Inflection points
Let's find the inflection points, we'll need to solve the equation for this
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = $$
the second derivative
$$\frac{e^{\frac{y}{2}}}{4} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = 0$$
(the second derivative equals zero),
the roots of this equation will be the inflection points for the specified function graph:
$$\frac{d^{2}}{d y^{2}} f{\left(y \right)} = $$
the second derivative
$$\frac{e^{\frac{y}{2}}}{4} = 0$$
Solve this equation
Solutions are not found,
maybe, the function has no inflections
Horizontal asymptotes
Let’s find horizontal asymptotes with help of the limits of this function at y->+oo and y->-oo
$$\lim_{y \to -\infty} \sqrt{e^{y}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{y \to \infty} \sqrt{e^{y}} = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
$$\lim_{y \to -\infty} \sqrt{e^{y}} = 0$$
Let's take the limit
so,
equation of the horizontal asymptote on the left:
$$y = 0$$
$$\lim_{y \to \infty} \sqrt{e^{y}} = \infty$$
Let's take the limit
so,
horizontal asymptote on the right doesn’t exist
Inclined asymptotes
Inclined asymptote can be found by calculating the limit of sqrt(E^y), divided by y at y->+oo and y ->-oo
$$\lim_{y \to -\infty}\left(\frac{e^{\frac{y}{2}}}{y}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{y \to \infty}\left(\frac{e^{\frac{y}{2}}}{y}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
$$\lim_{y \to -\infty}\left(\frac{e^{\frac{y}{2}}}{y}\right) = 0$$
Let's take the limit
so,
inclined coincides with the horizontal asymptote on the right
$$\lim_{y \to \infty}\left(\frac{e^{\frac{y}{2}}}{y}\right) = \infty$$
Let's take the limit
so,
inclined asymptote on the right doesn’t exist
Even and odd functions
Let's check, whether the function even or odd by using relations f = f(-y) и f = -f(-y).
So, check:
$$\sqrt{e^{y}} = e^{- \frac{y}{2}}$$
- No
$$\sqrt{e^{y}} = - e^{- \frac{y}{2}}$$
- No
so, the function
not is
neither even, nor odd
So, check:
$$\sqrt{e^{y}} = e^{- \frac{y}{2}}$$
- No
$$\sqrt{e^{y}} = - e^{- \frac{y}{2}}$$
- No
so, the function
not is
neither even, nor odd