Mister Exam

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  • Identical expressions

  • - two *t*(tan(atan(t^ two) + one)^ two + one)/(t^ four + one) = zero
  • minus 2 multiply by t multiply by ( tangent of ( arc tangent of gent of (t squared ) plus 1) squared plus 1) divide by (t to the power of 4 plus 1) equally 0
  • minus two multiply by t multiply by ( tangent of ( arc tangent of gent of (t to the power of two) plus one) to the power of two plus one) divide by (t to the power of four plus one) equally zero
  • -2*t*(tan(atan(t2) + 1)2 + 1)/(t4 + 1) = 0
  • -2*t*tanatant2 + 12 + 1/t4 + 1 = 0
  • -2*t*(tan(atan(t²) + 1)² + 1)/(t⁴ + 1) = 0
  • -2*t*(tan(atan(t to the power of 2) + 1) to the power of 2 + 1)/(t to the power of 4 + 1) = 0
  • -2t(tan(atan(t^2) + 1)^2 + 1)/(t^4 + 1) = 0
  • -2t(tan(atan(t2) + 1)2 + 1)/(t4 + 1) = 0
  • -2ttanatant2 + 12 + 1/t4 + 1 = 0
  • -2ttanatant^2 + 1^2 + 1/t^4 + 1 = 0
  • -2*t*(tan(atan(t^2) + 1)^2 + 1) divide by (t^4 + 1) = 0
  • Similar expressions

  • -2*t*(tan(atan(t^2) - 1)^2 + 1)/(t^4 + 1) = 0
  • -2*t*(tan(atan(t^2) + 1)^2 - 1)/(t^4 + 1) = 0
  • -2*t*(tan(atan(t^2) + 1)^2 + 1)/(t^4 - 1) = 0
  • 2*t*(tan(atan(t^2) + 1)^2 + 1)/(t^4 + 1) = 0
  • -2*t*(tan(arctan(t^2) + 1)^2 + 1)/(t^4 + 1) = 0

-2*t*(tan(atan(t^2) + 1)^2 + 1)/(t^4 + 1) = 0 equation

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Numerical solution:

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