Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -17*x+14*y=11
- -1*x-17*y=10
- 3*x+3*y=10
- 12*x+12*y=-3
- Equation:
-
Equation x^2+2x+1=0
-
Equation cos(x/2)=1/2
-
Equation (x+7)*(x-1)=0
-
Equation -4/7*x^2+28=0
- Integral of d{x}:
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-1
- Derivative of:
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-1
- Sum of series:
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-1
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Identical expressions
- - sixteen *x+ thirteen *y=- one
- minus 16 multiply by x plus 13 multiply by y equally minus 1
- minus sixteen multiply by x plus thirteen multiply by y equally minus one
- -16x+13y=-1
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Similar expressions
- -16*x+13*y=+1
- 16*x+13*y=-1
- -16*x-13*y=-1
Express x in terms of y where -16*x+13*y=-1
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = - 13 y - 1$$
Divide both parts of the equation by -16
We get the answer: x = 1/16 + 13*y/16
-16*x+13*y = -1
Looking for similar summands in the left part:
-16*x + 13*y = -1
Move the summands with the other variables
from left part to right part, we given:
$$- 16 x = - 13 y - 1$$
Divide both parts of the equation by -16
x = -1 - 13*y / (-16)
We get the answer: x = 1/16 + 13*y/16
Rapid solution
[src]
1 13*re(y) 13*I*im(y)
x1 = -- + -------- + ----------
16 16 16
$$x_{1} = \frac{13 \operatorname{re}{\left(y\right)}}{16} + \frac{13 i \operatorname{im}{\left(y\right)}}{16} + \frac{1}{16}$$
x1 = 13*re(y)/16 + 13*i*im(y)/16 + 1/16