Mister Exam
Other calculators
-
How to use it?
- Express {x} in terms of y where:
- -11*x-3*y=14
- -1*x-17*y=-12
- 20*x+18*y=-9
- -2*x+20*y=-2
- Equation:
-
Equation x/4+x=4
-
Equation x^2+11=0
- Equation x+y=5
-
Equation 1*(x-1)*(x-3)=0
- Sum of series:
-
19
- Integral of d{x}:
- 19
- Limit of the function:
- 19
-
Identical expressions
- - six *x+ ten *y= nineteen
- minus 6 multiply by x plus 10 multiply by y equally 19
- minus six multiply by x plus ten multiply by y equally nineteen
- -6x+10y=19
-
Similar expressions
- 6*x+10*y=19
- -6*x-10*y=19
Express x in terms of y where -6*x+10*y=19
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 19 - 10 y$$
Divide both parts of the equation by -6
We get the answer: x = -19/6 + 5*y/3
-6*x+10*y = 19
Looking for similar summands in the left part:
-6*x + 10*y = 19
Move the summands with the other variables
from left part to right part, we given:
$$- 6 x = 19 - 10 y$$
Divide both parts of the equation by -6
x = 19 - 10*y / (-6)
We get the answer: x = -19/6 + 5*y/3
Rapid solution
[src]
19 5*re(y) 5*I*im(y)
x1 = - -- + ------- + ---------
6 3 3
$$x_{1} = \frac{5 \operatorname{re}{\left(y\right)}}{3} + \frac{5 i \operatorname{im}{\left(y\right)}}{3} - \frac{19}{6}$$
x1 = 5*re(y)/3 + 5*i*im(y)/3 - 19/6