Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -2*x+4*y=3
- 3*x-17*y=-6
- 3*x-2*y=-9
- -5*x-9*y=-18
- Equation:
-
Equation (x+7)*(x-1)=0
-
Equation sin(x)=0
-
Equation 2(y+3)=21-3y
- Equation x^3-25*x=0
- Integral of d{x}:
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-3
- Derivative of:
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-3
- Sum of series:
-
-3
-
Identical expressions
- - nine *x- seventeen *y=- three
- minus 9 multiply by x minus 17 multiply by y equally minus 3
- minus nine multiply by x minus seventeen multiply by y equally minus three
- -9x-17y=-3
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Similar expressions
- 9*x-17*y=-3
- -9*x+17*y=-3
- -9*x-17*y=+3
Express x in terms of y where -9*x-17*y=-3
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$- 9 x = 17 y - 3$$
Divide both parts of the equation by -9
We get the answer: x = 1/3 - 17*y/9
-9*x-17*y = -3
Looking for similar summands in the left part:
-17*y - 9*x = -3
Move the summands with the other variables
from left part to right part, we given:
$$- 9 x = 17 y - 3$$
Divide both parts of the equation by -9
x = -3 + 17*y / (-9)
We get the answer: x = 1/3 - 17*y/9
Rapid solution
[src]
1 17*re(y) 17*I*im(y)
x1 = - - -------- - ----------
3 9 9
$$x_{1} = - \frac{17 \operatorname{re}{\left(y\right)}}{9} - \frac{17 i \operatorname{im}{\left(y\right)}}{9} + \frac{1}{3}$$
x1 = -17*re(y)/9 - 17*i*im(y)/9 + 1/3