Mister Exam
Other calculators
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How to use it?
- Express {x} in terms of y where:
- -4*x+7*y=-16
- -1*x-20*y=1
- 14*x-10*y=-4
- -11*x+16*y=3
- Equation:
- Equation ax=b
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Equation x^2-x+8=0
- Equation x^2+y^2=1
-
Equation x^2-8x+16=0
- Sum of series:
-
-8
- Integral of d{x}:
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-8
- Limit of the function:
- -8
-
Identical expressions
- fifteen *x+ three *y=- eight
- 15 multiply by x plus 3 multiply by y equally minus 8
- fifteen multiply by x plus three multiply by y equally minus eight
- 15x+3y=-8
-
Similar expressions
- 15*x-3*y=-8
- 15*x+3*y=+8
Express x in terms of y where 15*x+3*y=-8
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$15 x = - 3 y - 8$$
Divide both parts of the equation by 15
We get the answer: x = -8/15 - y/5
15*x+3*y = -8
Looking for similar summands in the left part:
3*y + 15*x = -8
Move the summands with the other variables
from left part to right part, we given:
$$15 x = - 3 y - 8$$
Divide both parts of the equation by 15
x = -8 - 3*y / (15)
We get the answer: x = -8/15 - y/5
Rapid solution
[src]
8 re(y) I*im(y)
x1 = - -- - ----- - -------
15 5 5
$$x_{1} = - \frac{\operatorname{re}{\left(y\right)}}{5} - \frac{i \operatorname{im}{\left(y\right)}}{5} - \frac{8}{15}$$
x1 = -re(y)/5 - i*im(y)/5 - 8/15