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y+(430/41+120/41)=82/41-15/41 equation

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Numerical solution:

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The solution

You have entered [src]
    430   120       15
y + --- + --- = 2 - --
     41    41       41
$$y + \left(\frac{120}{41} + \frac{430}{41}\right) = - \frac{15}{41} + 2$$
Detail solution
Given the linear equation:
y+(430/41+120/41) = 82/41-15/41

Expand brackets in the left part
y+430/41+120/41 = 82/41-15/41

Looking for similar summands in the left part:
550/41 + y = 82/41-15/41

Looking for similar summands in the right part:
550/41 + y = 67/41

Move free summands (without y)
from left part to right part, we given:
$$y = - \frac{483}{41}$$
We get the answer: y = -483/41
The graph
Rapid solution [src]
     -483 
y1 = -----
       41 
$$y_{1} = - \frac{483}{41}$$
y1 = -483/41
Sum and product of roots [src]
sum
-483 
-----
  41 
$$- \frac{483}{41}$$
=
-483 
-----
  41 
$$- \frac{483}{41}$$
product
-483 
-----
  41 
$$- \frac{483}{41}$$
=
-483 
-----
  41 
$$- \frac{483}{41}$$
-483/41
Numerical answer [src]
y1 = -11.780487804878
y1 = -11.780487804878