y+(430/41+120/41)=82/41-15/41 equation
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The solution
Detail solution
Given the linear equation:
y+(430/41+120/41) = 82/41-15/41
Expand brackets in the left part
y+430/41+120/41 = 82/41-15/41
Looking for similar summands in the left part:
550/41 + y = 82/41-15/41
Looking for similar summands in the right part:
550/41 + y = 67/41
Move free summands (without y)
from left part to right part, we given:
$$y = - \frac{483}{41}$$
We get the answer: y = -483/41
$$y_{1} = - \frac{483}{41}$$
Sum and product of roots
[src]
$$- \frac{483}{41}$$
$$- \frac{483}{41}$$
$$- \frac{483}{41}$$
$$- \frac{483}{41}$$