(x+10)^2=(x-9)^2 equation
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The solution
Detail solution
Given the equation:
(x+10)^2 = (x-9)^2
Expand expressions:
100 + x^2 + 20*x = (x-9)^2
(x+10)^2 = 81 + x^2 - 18*x
Reducing, you get:
19 + 38*x = 0
Move free summands (without x)
from left part to right part, we given:
$$38 x = -19$$
Divide both parts of the equation by 38
x = -19 / (38)
We get the answer: x = -1/2
Sum and product of roots
[src]
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$- \frac{1}{2}$$
$$x_{1} = - \frac{1}{2}$$