Mister Exam
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How to use it?
- Equation:
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Equation 9x-6(x-1)=5(x+2)
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Equation x^6=5
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Equation 5x(x-4)-x(3+5x)=4
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Equation k^2-4*k+3=0
- Express {x} in terms of y where:
- 15*x+15*y=16
- 8*x+7*y=-13
- -4*x+18*y=-14
- 14*x-16*y=14
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Identical expressions
- 5x(x- four)-x(three +5x)= four
- 5x(x minus 4) minus x(3 plus 5x) equally 4
- 5x(x minus four) minus x(three plus 5x) equally four
- 5xx-4-x3+5x=4
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Similar expressions
- 5x(x-4)+x(3+5x)=4
- 5x(x-4-x(3+5x))=4
- 5x(x-4)-x(3-5x)=4
- 5x(x+4)-x(3+5x)=4
5x(x-4)-x(3+5x)=4 equation
The teacher will be very surprised to see your correct solution 😉
The solution
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[src]
5*x*(x - 4) - x*(3 + 5*x) = 4
$$- x \left(5 x + 3\right) + 5 x \left(x - 4\right) = 4$$
Detail solution
Given the linear equation:
Expand brackets in the left part
Looking for similar summands in the left part:
Move free summands (without x)
from left part to right part, we given:
$$5 x \left(x - 4\right) - x \left(5 x + 3\right) + 4 = 8$$
Divide both parts of the equation by (4 - x*(3 + 5*x) + 5*x*(-4 + x))/x
We get the answer: x = -4/23
5*x*(x-4)-x*(3+5*x) = 4
Expand brackets in the left part
5*xx-4-x3+5*x = 4
Looking for similar summands in the left part:
-x*(3 + 5*x) + 5*x*(-4 + x) = 4
Move free summands (without x)
from left part to right part, we given:
$$5 x \left(x - 4\right) - x \left(5 x + 3\right) + 4 = 8$$
Divide both parts of the equation by (4 - x*(3 + 5*x) + 5*x*(-4 + x))/x
x = 8 / ((4 - x*(3 + 5*x) + 5*x*(-4 + x))/x)
We get the answer: x = -4/23
Sum and product of roots
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sum
-4/23
$$- \frac{4}{23}$$
=
-4/23
$$- \frac{4}{23}$$
product
-4/23
$$- \frac{4}{23}$$
=
-4/23
$$- \frac{4}{23}$$
-4/23
The graph