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(5-x)^2-x*((5/2)+x)=0

(5-x)^2-x*((5/2)+x)=0 equation

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Numerical solution:

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The solution

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(5 - x)  - x*(5/2 + x) = 0
$$- x \left(x + \frac{5}{2}\right) + \left(5 - x\right)^{2} = 0$$
Detail solution
Given the equation:
(5-x)^2-x*((5/2)+x) = 0

Expand expressions:
25 + x^2 - 10*x - x*(5/2 + x) = 0

25 + x^2 - 10*x - x^2 - 5*x/2 = 0

Reducing, you get:
25 - 25*x/2 = 0

Move free summands (without x)
from left part to right part, we given:
$$- \frac{25 x}{2} = -25$$
Divide both parts of the equation by -25/2
x = -25 / (-25/2)

We get the answer: x = 2
The graph
Sum and product of roots [src]
sum
2
$$2$$
=
2
$$2$$
product
2
$$2$$
=
2
$$2$$
2
Rapid solution [src]
x1 = 2
$$x_{1} = 2$$
x1 = 2
Numerical answer [src]
x1 = 2.0
x1 = 2.0
The graph
(5-x)^2-x*((5/2)+x)=0 equation