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k^2-5*k+6=0

k^2-5*k+6=0 equation

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Numerical solution:

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The solution

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 2              
k  - 5*k + 6 = 0
$$\left(k^{2} - 5 k\right) + 6 = 0$$
Detail solution
This equation is of the form
a*k^2 + b*k + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$k_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$k_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = -5$$
$$c = 6$$
, then
D = b^2 - 4 * a * c = 

(-5)^2 - 4 * (1) * (6) = 1

Because D > 0, then the equation has two roots.
k1 = (-b + sqrt(D)) / (2*a)

k2 = (-b - sqrt(D)) / (2*a)

or
$$k_{1} = 3$$
$$k_{2} = 2$$
Vieta's Theorem
it is reduced quadratic equation
$$k^{2} + k p + q = 0$$
where
$$p = \frac{b}{a}$$
$$p = -5$$
$$q = \frac{c}{a}$$
$$q = 6$$
Vieta Formulas
$$k_{1} + k_{2} = - p$$
$$k_{1} k_{2} = q$$
$$k_{1} + k_{2} = 5$$
$$k_{1} k_{2} = 6$$
The graph
Sum and product of roots [src]
sum
2 + 3
$$2 + 3$$
=
5
$$5$$
product
2*3
$$2 \cdot 3$$
=
6
$$6$$
6
Rapid solution [src]
k1 = 2
$$k_{1} = 2$$
k2 = 3
$$k_{2} = 3$$
k2 = 3
Numerical answer [src]
k1 = 3.0
k2 = 2.0
k2 = 2.0
The graph
k^2-5*k+6=0 equation