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- Equation:
-
Equation 18-7x=10-3(x+4)
- Equation (3y+2)/(4y^2+y)+(y-3)/(16y^2-1)=3/(4y-1)
- Equation (13+x)×12=80
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Equation cos(8x)=-(1/2)
- Express {x} in terms of y where:
- 5*x-5*y=20
- 8*x-7*y=-13
- 15*x-15*y=16
- 9*x+18*y=6
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Identical expressions
- eighteen -7x= ten - three (x+ four)
- 18 minus 7x equally 10 minus 3(x plus 4)
- eighteen minus 7x equally ten minus three (x plus four)
- 18-7x=10-3x+4
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Similar expressions
- 18x-7x=10-3*(x+4)
- x^2=18-7*x
- 18-7x=10+3(x+4)
- 18+7x=10-3(x+4)
- 18-7x=10-3(x-4)
18-7x=10-3(x+4) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Expand brackets in the right part
Looking for similar summands in the right part:
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$- 4 x = -20$$
Divide both parts of the equation by -4
We get the answer: x = 5
18-7*x = 10-3*(x+4)
Expand brackets in the right part
18-7*x = 10-3*x-3*4
Looking for similar summands in the right part:
18 - 7*x = -2 - 3*x
Move free summands (without x)
from left part to right part, we given:
$$- 7 x = - 3 x - 20$$
Move the summands with the unknown x
from the right part to the left part:
$$- 4 x = -20$$
Divide both parts of the equation by -4
x = -20 / (-4)
We get the answer: x = 5
Sum and product of roots
[src]
sum
5
$$\left(5\right)$$
=
5
$$5$$
product
5
$$\left(5\right)$$
=
5
$$5$$
The graph