8*(26-x)=5*(26-y) equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
8*(26-x) = 5*(26-y)
Expand brackets in the left part
8*26-8*x = 5*(26-y)
Expand brackets in the right part
8*26-8*x = 5*26-5*y
Move free summands (without x)
from left part to right part, we given:
$$- 8 x = - 5 y - 78$$
Divide both parts of the equation by -8
x = -78 - 5*y / (-8)
We get the answer: x = 39/4 + 5*y/8
Sum and product of roots
[src]
39 5*re(y) 5*I*im(y)
-- + ------- + ---------
4 8 8
$$\frac{5 \operatorname{re}{\left(y\right)}}{8} + \frac{5 i \operatorname{im}{\left(y\right)}}{8} + \frac{39}{4}$$
39 5*re(y) 5*I*im(y)
-- + ------- + ---------
4 8 8
$$\frac{5 \operatorname{re}{\left(y\right)}}{8} + \frac{5 i \operatorname{im}{\left(y\right)}}{8} + \frac{39}{4}$$
39 5*re(y) 5*I*im(y)
-- + ------- + ---------
4 8 8
$$\frac{5 \operatorname{re}{\left(y\right)}}{8} + \frac{5 i \operatorname{im}{\left(y\right)}}{8} + \frac{39}{4}$$
39 5*re(y) 5*I*im(y)
-- + ------- + ---------
4 8 8
$$\frac{5 \operatorname{re}{\left(y\right)}}{8} + \frac{5 i \operatorname{im}{\left(y\right)}}{8} + \frac{39}{4}$$
39/4 + 5*re(y)/8 + 5*i*im(y)/8
39 5*re(y) 5*I*im(y)
x1 = -- + ------- + ---------
4 8 8
$$x_{1} = \frac{5 \operatorname{re}{\left(y\right)}}{8} + \frac{5 i \operatorname{im}{\left(y\right)}}{8} + \frac{39}{4}$$
x1 = 5*re(y)/8 + 5*i*im(y)/8 + 39/4