Mister Exam
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How to use it?
- Equation:
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Equation -x=4-3(3x-8)
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Equation x/9+x=-10/3
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Equation √(x^2-1)=2*x
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Equation 4(x-3)=x+6
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- 17*x+20*y=-12
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Identical expressions
- 5a+8b= thirty .
- 5a plus 8b equally 30.
- 5a plus 8b equally thirty .
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Similar expressions
- 5a-8b=30.
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- x^2+3x-4=(7+273^0.5)/2
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5a+8b=30. equation
The teacher will be very surprised to see your correct solution 😉
The solution
Detail solution
Given the linear equation:
Looking for similar summands in the left part:
Move the summands with the other variables
from left part to right part, we given:
$$5 a = 30 - 8 b$$
Divide both parts of the equation by 5
We get the answer: a = 6 - 8*b/5
5*a+8*b = 30
Looking for similar summands in the left part:
5*a + 8*b = 30
Move the summands with the other variables
from left part to right part, we given:
$$5 a = 30 - 8 b$$
Divide both parts of the equation by 5
a = 30 - 8*b / (5)
We get the answer: a = 6 - 8*b/5
The graph
Rapid solution
[src]
8*re(b) 8*I*im(b)
a1 = 6 - ------- - ---------
5 5
$$a_{1} = - \frac{8 \operatorname{re}{\left(b\right)}}{5} - \frac{8 i \operatorname{im}{\left(b\right)}}{5} + 6$$
a1 = -8*re(b)/5 - 8*i*im(b)/5 + 6
Sum and product of roots
[src]
sum
8*re(b) 8*I*im(b)
6 - ------- - ---------
5 5
$$- \frac{8 \operatorname{re}{\left(b\right)}}{5} - \frac{8 i \operatorname{im}{\left(b\right)}}{5} + 6$$
=
8*re(b) 8*I*im(b)
6 - ------- - ---------
5 5
$$- \frac{8 \operatorname{re}{\left(b\right)}}{5} - \frac{8 i \operatorname{im}{\left(b\right)}}{5} + 6$$
product
8*re(b) 8*I*im(b)
6 - ------- - ---------
5 5
$$- \frac{8 \operatorname{re}{\left(b\right)}}{5} - \frac{8 i \operatorname{im}{\left(b\right)}}{5} + 6$$
=
8*re(b) 8*I*im(b)
6 - ------- - ---------
5 5
$$- \frac{8 \operatorname{re}{\left(b\right)}}{5} - \frac{8 i \operatorname{im}{\left(b\right)}}{5} + 6$$
6 - 8*re(b)/5 - 8*i*im(b)/5