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(x+10)^2=(5-x)^2

(x+10)^2=(5-x)^2 equation

A equation with variable:

Numerical solution:

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The solution

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        2          2
(x + 10)  = (5 - x) 
$$\left(x + 10\right)^{2} = \left(5 - x\right)^{2}$$
Detail solution
Given the equation:
(x+10)^2 = (5-x)^2

Expand expressions:
100 + x^2 + 20*x = (5-x)^2

(x+10)^2 = 25 + x^2 - 10*x

Reducing, you get:
75 + 30*x = 0

Move free summands (without x)
from left part to right part, we given:
$$30 x = -75$$
Divide both parts of the equation by 30
x = -75 / (30)

We get the answer: x = -5/2
The graph
Sum and product of roots [src]
sum
-5/2
$$- \frac{5}{2}$$
=
-5/2
$$- \frac{5}{2}$$
product
-5/2
$$- \frac{5}{2}$$
=
-5/2
$$- \frac{5}{2}$$
-5/2
Rapid solution [src]
x1 = -5/2
$$x_{1} = - \frac{5}{2}$$
x1 = -5/2
Numerical answer [src]
x1 = -2.5
x1 = -2.5
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