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y^2+1 equation

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Numerical solution:

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The solution

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 2        
y  + 1 = 0
$$y^{2} + 1 = 0$$
Detail solution
This equation is of the form
a*y^2 + b*y + c = 0

A quadratic equation can be solved
using the discriminant.
The roots of the quadratic equation:
$$y_{1} = \frac{\sqrt{D} - b}{2 a}$$
$$y_{2} = \frac{- \sqrt{D} - b}{2 a}$$
where D = b^2 - 4*a*c - it is the discriminant.
Because
$$a = 1$$
$$b = 0$$
$$c = 1$$
, then
D = b^2 - 4 * a * c = 

(0)^2 - 4 * (1) * (1) = -4

Because D<0, then the equation
has no real roots,
but complex roots is exists.
y1 = (-b + sqrt(D)) / (2*a)

y2 = (-b - sqrt(D)) / (2*a)

or
$$y_{1} = i$$
$$y_{2} = - i$$
Vieta's Theorem
it is reduced quadratic equation
$$p y + q + y^{2} = 0$$
where
$$p = \frac{b}{a}$$
$$p = 0$$
$$q = \frac{c}{a}$$
$$q = 1$$
Vieta Formulas
$$y_{1} + y_{2} = - p$$
$$y_{1} y_{2} = q$$
$$y_{1} + y_{2} = 0$$
$$y_{1} y_{2} = 1$$
The graph
Sum and product of roots [src]
sum
-I + I
$$- i + i$$
=
0
$$0$$
product
-I*I
$$- i i$$
=
1
$$1$$
1
Rapid solution [src]
y1 = -I
$$y_{1} = - i$$
y2 = I
$$y_{2} = i$$
y2 = i
Numerical answer [src]
y1 = -1.0*i
y2 = 1.0*i
y2 = 1.0*i